15x^2+3x=228x

Solution for 15x^2+3x=228x equation:

15x^2+3x=228x

We move all terms to the left:

15x^2+3x-(228x)=0

We add all the numbers together, and all the variables

15x^2-225x=0

a = 15; b = -225; c = 0;
Δ = b2-4ac
Δ = -2252-4·15·0
Δ = 50625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50625}=225$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-225}{2*15}=\frac{0}{30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+225}{2*15}=\frac{450}{30}
=15
$